Use Newton’s laws to calculate the force of friction. Remember that the shoe is moving at constant velocity. How must the applied force compare to the force of kinetic friction? From the force of friction, calculate the coefficient of kinetic friction for each trial. Plot the force of friction vs. the weight for each trial of each shoe. You will have two lines on the same graph, one for each shoe. Calculate the slope of each line and write it down. Someone please help this is due today and i have no idea how to do it.
here is the table
Welcome to OS! Sorry I haven't quite done friction yet (actually supposed to start it next week). We can try to learn this together. Do you know how to calculate the frictional force? After that the next step would be to plot the graph.
no i dont really understand how to calculate frictional force
i looked up the equation for it and got Ffrict=the mew symbol*Fnorm
Ok, that's what I'm getting, too. Since the acceleration is 0 (constant velocity) we know that: \[\Sigma F = ma\] \[F_{app} - F_{k} = ma\] And since ma = 0 (cause anything times 0 is 0) \[F_{app} = F_{k}\] Does that sound right?
yes sort of
so how would we set up fapp=fk
here is the lab table again only that i converted the weight into kilograms and grams
Sorry it took me so long. Since the applied force equals the kinetic frictional force, you can put that in the table and graph it, I think? It wanted you to graph frictional force versus weight.
wait im confused what is the kinetic frictional then i know what my applied force is but not the kinetic
as @SapphireMoon said, \(F_f = F _a\) because the shoe has constant velocity weight and friction force are related as \(F_f = \mu W\) so \(\dfrac{F_f}{W} = \mu \) so the slope of ypur lines will be \(\mu\), ie the coefficient of kinetic (moving or sliding) friction the sports shoes should have greater friction |dw:1478194584192:dw|
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