Question

ple

Answer 1

Your idea?

Answer 2

I believe it is B, but not sure

Answer 3

How?

Answer 4

because of my work in my notebook but i think its wrong- am i?

Answer 5

Nope.

Answer 6

It is not correct

Answer 7

first notice the -x^2
graph should look like
so a maximum will exist

then take the first derivative and determine the critical value

once you have critical value, substittue it back into the original equation.

that being said, what critical value did you get?

Answer 8

Sorry!
I was busy.

Answer 9

@3mar ok.. then can you help me now please?

Answer 10

Where are you stuck?

Answer 11

@3mar I know you are here and please is it the limit does not exist for the first one?

Answer 12

or would it be 4250

Answer 13

As it is a negative-slope parabola (-x^2), so it has a maximum value at its vertex.

Can you find out its vertex?

Answer 14

@iwanttogotostanford
Can you kindly respond more faster, please?

Answer 15

@3mar so sorry my computer is slow I have found out that it is 4.250

Answer 16

Yes you are correct!

4.25 is the value of the function at its maximum point!

Answer 17

ok, may i ask you one more?

Answer 18

Can we start in new post, please?

Answer 19

yes please come fast

Answer 20

Thanks.
just you respond faster!