Question

Given the function f(x) = 3(x+2) − 4, solve for the inverse function when x = 2.

−4
0
4
8

Answer 1

If I may help?

Answer 2

Please do

Answer 3

Thank you.

Answer 4

Can you find out the inverse o this function firstly?

Answer 5

I know that the inverse can be found but I am unsure how to

Answer 6

can someone help me

Answer 7

Can you share what you got and I check it for you?

Answer 8

Can anyone help me with a doc

Answer 9

I didn't get an answer because I'm unsure how to solve for the inverse of f(x)

Answer 10

Of course, which is?

Answer 11

@macgirl234

Do you follow?

Answer 12

Can we proceed here?
http://openstudy.com/study#/updates/581ba2cce4b03ac563220145

Answer 13

sure.

Answer 14

Sorry for misunderstanding!

Answer 15

no problem!

Answer 16

Could you give me the formula or steps to follow to solve for the inverse of f(x) then I can attempt to apply it to the problem?

Answer 17

Welcome back!
♥ ♥
♥

Answer 18

Of course.
With my pleasure!

Answer 19

Here are the steps:
1. If you are given a function y(x), first off you solve it for y, which means separate y in one side and the other terms in the other side.

2. solve for x, also separate x in one side and the other terms in the other side including y.

3. swap x and y.......you get the invrse.


\[\huge hint\]
the inverse of a function is the reflection of the original function about the line (y=x).

That is for you to simply imagine it and makes sense for you!!

Answer 20

So, I would solve for y, solve for x, then flip them?

Answer 21

For our case:
f(x) = 3(x+2) − 4

\[y=3(x+2)−4\]

solve for x:
\[y+4=3(x+2)−4+4\]
\[y+4=3(x+2)\]
\[y+4=3x+6\]
\[y+4-6=3x+6-6\]
\[y+4-6=3x\]
\[\frac{ y-2 }{ 3 }= \frac{ 3x }{ 3 }\]
\[\huge x=\frac{ y-2 }{ 3 }\]

now swap x and y::::

\[\huge y=\frac{ x-2 }{ 3 }\]
This is the inverse or the main function you are given!

Answer 22

@macgirl234
Satisfied?

Answer 23

Ahhhhhh!!! and then if x=2, that means that
y= 2-2/3
y=0/3
y=0
Correct?

Answer 24

Excellent!

Answer 25

Woohoo!!! Thanks so much!

Answer 26

Thank you for learning!

Answer 27

Any more questions?

Answer 28

Not with this question but I do have other questions for different problems.

Answer 29

I wouldn't want to take up all of your time though.

Answer 30

At your service!

Answer 31

Are you sure?

Answer 32

Let me surprise you!