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Mathematics 9 Online
OpenStudy (itrymath):

Look at the quadrilateral shown below. Terra writes the following proof for the theorem, If the diagonals of a quadrilateral bisect each other, the quadrilateral is a parallelogram. Terra's proof 1. AO = OC because it is given that diagonals bisect each other. 2. BO = OD because it is given that diagonals bisect each other. 3. For triangles AOB and COD, angle 1 is equal to angle 2 as they are supplemental angles. 4. Therefore, the triangles AOB and COD are congruent by SAS postulate. 5. Similarly, triangles AOD and COB are congruent. 6. By CPCTC, angle ABD is equal to angle BDC

OpenStudy (itrymath):

Look at the quadrilateral shown below. Terra writes the following proof for the theorem, If the diagonals of a quadrilateral bisect each other, the quadrilateral is a parallelogram. Terra's proof 1. AO = OC because it is given that diagonals bisect each other. 2. BO = OD because it is given that diagonals bisect each other. 3. For triangles AOB and COD, angle 1 is equal to angle 2 as they are supplemental angles. 4. Therefore, the triangles AOB and COD are congruent by SAS postulate. 5. Similarly, triangles AOD and COB are congruent. 6. By CPCTC, angle ABD is equal to angle BDC and angle ADB is equal to angle DBC. 7. As the alternate interior angles are congruent the opposite sides of quadrilateral ABCD are parallel. 8. Therefore, ABCD is a parallelogram. Which is the first incorrect statement in Terra's proof? (5 points) Statement 2 Statement 3 Statement 1 Statement 4

OpenStudy (itrymath):

OpenStudy (itrymath):

@3mar @pooja195 @mathmate @jim_thompson5910

OpenStudy (3mar):

One minute, please!

OpenStudy (madr4t):

statement 3 is wrong because they are not supplement angles

OpenStudy (itrymath):

I KNEW IT!!!! my internet turned off idk why but it did and didnt send my message!!!

OpenStudy (itrymath):

IM GETTING SO GOOD AT THIS!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (madr4t):

lol good job!

OpenStudy (madr4t):

also thank you

OpenStudy (itrymath):

:) enjoy my testimonial

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