Please I need help.
A 1-kg block of wood is dropped from a height 2.26 meters above a resting 0.05-kg ball. Shortly thereafter, the ball is shot horizontally at a velocity of 2.91 m/s. The wood is 9.94 meters away from the ball in the horizontal direction.
Determine the distance (in meters) the wood falls from its original position until impact? Ignore air resistance.

Question

Please I need help.
A 1-kg block of wood is dropped from a height 2.26 meters above a resting 0.05-kg ball. Shortly thereafter, the ball is shot horizontally at a velocity of 2.91 m/s. The wood is 9.94 meters away from the ball in the horizontal direction.
Determine the distance (in meters) the wood falls from its original position until impact? Ignore air resistance.

518nad · Answer

solved this for u earlier

steve816 · Answer

a=9.81m/s
v=9.81 * t
d=9.81/2*t^2
d=9.81/2*(9.94/2.91)^2

steve816 · Answer

This is what you said earlier, and I'm still confused. I put your answer in my calculator and got 57.23, how is that a possible answer if the wood is dropped from 2.26 meters above?

sooobored · Answer

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steve816 · Answer

http://www.webassign.net/userimages/prob2.gif?db=v4net&id=52910

sooobored · Answer

such a weird problem

steve816 · Answer

I know right? Blame my physics teacher and webassign. Do you think you can help @sooobored ?

sooobored · Answer

the shortly thereafter is... not very nice and vague

sooobored · Answer

ill give it a shot

sooobored · Answer

block of wood- at no initial velocity, and has initial height which i will define as h+2.26

ball- initial height of h, initial x velocity of 2.91m/s, 9.94m away from block in horizontal direction

sooobored · Answer

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