Question

can anyone help me to factor out 4x^2+4x-3?
I'm not sure how to get the end result, I know it is (2x-1)(2x+3) but I don't know how to work it out to get to that.

Answer 1

ok I found out how to do it finally

Answer 2

Nice job then!

Answer 3

@fearbigJJRob
In case you're still interested in having a systematic way to factor the quadratic, you can do it as follows.

The product of the first and last coefficient is 4*(-3)=-12
You look for two numbers whose product is -12 and sum +4 (middle coefficient).
By trial and error with integers, you find +6 and -2.
NOW, you rewrite the quadratic as:
4x^2\(\color{red}{+6}\)x \(\color{red}{-2}\)x-3
=2x(2x+3) - (2x+3)
=(2x-1)(2x+3)