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Mathematics
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Evaluate the integral
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\[I=\int\limits_{0}^{\pi/6} (\frac{ 3 }{ \cos^2\theta }+2\cos \theta ) d \theta \]
cos = 1/sec ya?
yup
\[\large\rm I=\int\limits\limits_{0}^{\pi/6} 3\sec^2\theta+2\cos\theta~d\theta\]
Sooo, where you stuck? :) These terms should integrate really nice and easy.
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ahh got it. I just forgot about sec being 1/cos >.< Thanks!
|dw:1478393895788:dw|Mmm yes! Very good, carry on!
Lol thank you, love the cat :D
^^^ Teach me how to do that ^^^ @zepdrix
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