Question

xy-3x^2=y
implict difference

Answer 1

@triciaal @steve816

Answer 2

\[\frac{ d }{ dx }[xy]+\frac{ d }{ dx }[-3x^2]=\frac{ d }{ dx }[y]\]

Answer 3

The hardest part is using the product rule on the first term. Do you know how to?

Answer 4

no :(

Answer 5

this is something i got \[x (dy/dx) +y-6x=1 dy/dx\]

Answer 6

yes,
\[x \frac{ dy }{ dx }+y-6x=\frac{ dy }{ dx }\]
is correct so far.
You need to isolate \(\frac{ dy }{ dx }\)

Answer 7

-y+6x ?

Answer 8

how would i isloate it

Answer 9

it's easier to type y' for dy/dx
move all the y' terms to one side, and everything else to the other side

Answer 10

Agreed, I thought showing the operator might be helpful.

Answer 11

i yet dont know what to do

Answer 12

ok i got it \[dy/dx= (6x-y)/(x-1)\]

Answer 13

thanks