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Mathematics 8 Online
OpenStudy (18jonea):

@3mar

OpenStudy (18jonea):

OpenStudy (3mar):

Can you share your works/steps, please?

OpenStudy (18jonea):

i have this example, just not sure with the fractions and everything

OpenStudy (18jonea):

OpenStudy (18jonea):

i think it would either be a or c

OpenStudy (3mar):

This one does not relate to ours!

OpenStudy (18jonea):

then im not really sure

OpenStudy (18jonea):

@3mar

OpenStudy (3mar):

Can you multiply by \(-2\) to make the coefficient of \(x^2\) equal to \(1\)??

OpenStudy (18jonea):

yes so 2/4 and 18/4

OpenStudy (3mar):

Can you please multiply by 2 again to eliminate the (1/2) at x?

OpenStudy (18jonea):

i dont get what you are saying

OpenStudy (3mar):

Can you please multiply by 2 again to not have any fraction in the equation?

OpenStudy (18jonea):

so 1x^2 ? sorry i am just confused

OpenStudy (18jonea):

@3mar

OpenStudy (3mar):

\[\Huge \frac{ -1 }{ 2 }x^2-\frac{ 7 }{ 4 }x-\frac{ 9 }{ 2 }=0\] multiply by -4 to eliminate all fractions: \[\huge -4*\frac{ -1 }{ 2 }*x^2+4*\frac{ 7 }{ 4 }x+4*\frac{ 9 }{ 2 }=0\] then \[\huge 2x^2+7x+18=0\] so \(a=2~~b=7~~c=18\) Can you now use the quadratic formula to solve such equation?

OpenStudy (3mar):

@18jonea

OpenStudy (18jonea):

yes

OpenStudy (3mar):

Let me see!

OpenStudy (18jonea):

hang on 2 seconds

OpenStudy (18jonea):

OpenStudy (18jonea):

@3mar

OpenStudy (3mar):

Brilliant! so the answer is ?

OpenStudy (18jonea):

a

OpenStudy (18jonea):

these next two i have solved but i just want you to double check is that ok?

OpenStudy (3mar):

You hit the right target! Yes it is A

OpenStudy (3mar):

I will not be late for any help. Any Help... Any Time...

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