Question

Can someone please help with math hw?

Answer 1

If I may help?

Answer 2

@3mar

Answer 3

1 min, please!

Answer 4

Well, I am here.
Can you proceed?

Answer 5

proceed with what?

Answer 6

with helping at hw?

Answer 7

Still need help?

Answer 8

yes I've been waiting...

Answer 9

Sorry for late.
let's start!

Answer 10

Where are you stuck?

Answer 11

everything

Answer 12

Do you have a Skype Id?

Answer 13

Can you kindly respond more faster, please?

Answer 14

no...can you just help me on open study

Answer 15

But here is more slower!
and you also late!

Answer 16

ill respond faster..lets just do it on here

Answer 17

ok so how do i prove they are inverses

Answer 18

Ok

Answer 19

Can you find the inverse of h(x)?

Answer 20

no thats why i am asking u

Answer 21

To get the inverse of any function f(x):
- solve for x, i.e separate x in one side and the other terms in the other side, included f(x).
- swap x and f(x).
- the final result is the inverse of the original function.

Answer 22

ok so how do i prove they are inverses

Answer 23

Start with h(x) and follow the steps above.

Answer 24

Or start with f(x), it is a bit easier!

Answer 25

\[f(x)=\sqrt{\frac{ x+5 }{ 2 }}+3\]
\[f(x)-3=\sqrt{\frac{ x+5 }{ 2 }}\]
square both sides
\[[f(x)-3]^2=\frac{ x+5 }{ 2 }\]
\[2[f(x)-3]^2= x+5\]
\[\Huge 2[f(x)-3]^2-5= x\]

Now: swap x and f(x)
\[\Huge 2[x-3]^2-5= f(x)\]
you can expand the parenthesis:
\[\Large f(x)=2[x-3]^2-5=2x^2-12x+18-5\]
\[\Huge f(x)=2x^2-12x+13\]

Answer 26

ohh ok thank you i get it!

Answer 27

You are welcome!
Pleasure is mine!

Answer 28

With a similar manner you can prove that h(x) is an inverse of f(x).

Answer 29

@pflori1234_pop
Can you kindly respond more faster, please?

Answer 30

ok

Answer 31

so now graphically how would i find the coordinates?

Answer 32

Can we start in new post, please?

Answer 33

@pflori1234_pop
still here?

Answer 34

Let me know where you are back!