Ask your own question, for FREE!
Algebra 9 Online
OpenStudy (sundaesunday):

Doctors can use radioactive chemicals to treat some forms of cancer. The half life of a certain chemical is 9 days. A patient receives a treatment of 28 millicuries of the chemical.​ (A millicurie is a unit of ​ radioactivity.) How much of the chemical remains in the patient 18 days​ later?

likeabossssssss (likeabossssssss):

\(\Huge\color{#EB00FF}{\text{WELCOME}}\) \(\Huge\color{blue}{\text{TO}}\) \(\Huge\color{green}{\text{OPEN}}\)\(\Huge\color{purple }{\text{ STUDY!!!!!!!!!!!}}\) \(\Huge\heartsuit\)

OpenStudy (festinger):

After 18 days, 2 half life durations would have passed. Thus, the activity remaining is \[28*\frac{1}{2}*\frac{1}{2}=7mSv\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
1 day ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!