Question

Jessica stretches her arms out 0.6 m from the center of her body while holding a 2 kg mass in each hand. She then spins around on an ice rink at 1.1 m/s.
a What is the combined angular momentum of the masses?
b If she pulls her arms in to 0.15 m, what is her linear speed if the angular momentum remains constant?

Answer 1

@Elsa213

Answer 2

@goodfaze123

Answer 3

Jessica stretches her arms out 0.6 m from the center of her body while holding a 2 kg mass in each hand. She then spins around on an ice rink at 1.1 m/s. a. What is the combined angular momentum of the masses?
First, we use I = mr^2, where m = 2 kg and r = 0.6 m.
0.6 squared is .36.
We multiply that with 2 to receive the product of .72.
This is the moment of inertia, which we will be using in the problem below. L = I , where I is the moment of inertia above, and is 1.1 m/s. Multiplying ω ω them with each other gives us a product of 7.92, which is the angular momentum of the masses.
b. If she pulls her arms in to 0.15 m, what is her linear speed if the angular momentum remains constant? First, we use I = mr^2, where m = 2 kg and r = 0.15m. 0.15 becomes 0.0225, and multiplied with 2 is 0.045, giving us the moment of inertia to use in the formula below. L = I , where I is 0.045, and is 1.1 m/s. 1.1 times 0.045 is 0.0495, which is her ω ω linear speed.

Answer 4

hope i helped

Answer 5

Thank you

Answer 6

no problem