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How to find the derivative of this formula?
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\[(3x ^{3}/7)-(4/5x ^{3})\]
do you now how to find the derivative of \(x^3 \) ?
@phi would it be\[3x ^{2}\]
and if have a constant "out front" e.g. 3/7, you get \[ \frac{3}{7}\cdot 3 x^2 \] or \[ \frac{9}{7} x^2 \]
now do the same thing to the other term or you could have factored out x^3 \[ \left(\frac{3}{7}- \frac{4}{5} \right)x^3 \] and that mess is still just some fraction i.e. constant and the derivative would be that constant times 3 x^2
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unless the 2nd term is \[ -\frac{4}{5x^3} \] ? in which case, write it as \[ -\frac{4}{5}x^{-3} \]
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