Question

consider an object with mass = 2kg moving at a velocity of v= 5m/s. It traverses a distance of 7m before coming to a halt due to friction. How strong is the frictional force acting on the object assuming that it is constant across the trajectory?

Answer 1

akiaki28

consider an object with mass = 2kg moving at a velocity of v= 5m/s. It traverses a distance of 7m before coming to a halt due to friction. How strong is the frictional force acting on the object assuming that it is constant across the trajectory?
Kinematic equation for DECELERATION ...
v squared = u squared - 2 a s
0=5 squared-2 a 7
25=2 a 7
a = 25/(2x7)

The maths form of Newton's second law is often written
F=ma.
F = 2x25/(2x7)
F = 25/7
F =3.5714285714285714285714285714286
I think/hope.
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Answer 2

welcome to openstudy!!!

Answer 3

an kinematics and dynamics and Newton's laws and maybe ...

Answer 4

F=ma
F=?
m=mass is given
u jv to find out a=?

Answer 5

now use
v^2=u^2-2as

Answer 6

u,v, s. given
a=?

Answer 7

^^^^^

Answer 8

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