I need help ! fan and medal!
im here to help
@tylerraymond4
mmmm 1 is 8,0
I need a equation
lol
@breanna.rae What part are you not getting?
all of it, I'm not good at this at all
So for a, we need to write the equation for line 1, it is a horizontal line intercepting the y axis at 8. How do you write that?
I really don't know
If you wanted to write a line that had a slope of 3x and intercept 8 on the y axis, you would write \[y = 3x + 8\] Since Line 1 has no slope, but intercepts 8 on the y axis, we just write \[y = 8\]
Do you get it?
ohh okay yes I understand I think
What are you unsure about?
wait where did you get 3x from..?
this is simple math girl!
It was just an example..
ohh nvm you were just using 3x as an example?
so it would be 0x+8=y
Remember that 0 times any number, is 0, therefore it would just be y = 0 + 8
okay thank you, for line 2, would be something like, 2.5x+-2??
I'm sorry if I'm wrong, I'm not good at understanding this stuff
@ShadowLegendX u rock i medald u cuz ur doing amazing!
Line 2 has a line of \[y = \frac{ 3 }{ 4 }x - 2\]
Remember that slope is rise over run We had the point at -2, and our next point had risen up 3 units on the y axis, not 2.5. So we know that our rise is 3. Then we run over 4 units, to the right, to our next point, on Line 2.
That is how I got 3/4x
ohhh omg ok thank you so much
Do you know how to find a line that is parallel, and another line that is perpendicular, to line 2?
no xD I'm sorry
When two lines are parallel, it means that they both have the same slope, and therefore will never intercept each other.
If you have taken geometry(or if you will) you will know/find out that shapes are defined a lot based on their sides, and if they are parallel or perpendicular. This is used primarily when categorizing parallelograms. |dw:1478628958935:dw| This is a trapezoid, the line on the top, and the line on the bottom, will never intercept each other because they are parallel, if they were to run off to both sides infinitely.
|dw:1478629050068:dw|
They will never hit each other, because they will both be rising by the same amount of units, then running by the same amount of units
I'm taking geometry right now lol, I know what parallel lines are
Then how do we create a line parallel to Line 2
\[\frac{ 3 }{ 4}x -4\]
Correct
Remember to put y =
right thank you
Now what about a line perpendicular to \[y = \frac{ 3 }{ 4 }x - 2\]
Do you know the definition of a perpendicular line?
yes its a line that intersects at a right angle
So what can you do to create such a line?
idk how to put it into an equation
Do you know how to get a slope that is perpendicular to 3/4x
ugh nooo xc
I'll give you a hint, maybe it'll jog you memory. Opposite
your*
I would use negatives?
Close, but not quite there yet
or add instead of subtract
I'm sorry that I'm not understanding
I'll give you the full hint, opposite reciprocal
Opposite is talking about the sign, so instead of a positive, put a negative
And, a number multiplied by it's reciprocal, is 1 For example ;p \[\frac{ 3 }{ 4 } \times \frac{ 4 }{ 3 } = \frac{ 12 }{ 12 } = 1\]
So we need the reciprocal, with an opposite sign
\[-\frac{ 3 }{ 4 }x-2=y\] would this be right then?
No
Remember, reciprocal
when I graph it, it intersects into a right angle?
Yes
so why would that be wrong?
Because you did not use the reciprocal of 3/4
so how would I use that in the equation
I showed you the reciprocal of 3/4, a couple posts ago
yes I know \[\frac{ 3 }{ 4} \times \frac{ 4 }{ 3 } = \frac{ 12 }{ 12 } =1\]
So 4/3 is the reciprocal of 3/4, and you know what an opposite is. So create the opposite reciprocal of 3/4
\[-\frac{ 3 }{ 4 }\times-\frac{ 4 }{ 3 }\] ?would that be right
The opposite reciprocal of 3/4x is \[-\frac{ 4 }{ 3 }x\]
OHHHHHHH so it would be \[-\frac{ 4 }{ 3 }x-2=y\]
is that right? or am I wrong again?
You're right
You got it now?
THANK GOODNESS, thank you so much it means a lot, I understand it I think, thank you thank you
No problem
have a great day
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