Question

Polynomials

Answer 1

Think of a polynomial \(p(x)\) that, when divided by \(x^{100}\), gives constant remainder 1, and when divided by \((x-2)^3\), gives constant remainder 2.

Answer 2

alright sure

Answer 3

kx^100+1=p*(x-3)^3+2

Answer 4

k=c1*x^(100n) *c2*(x-2)^(3m)
p=c3*x^(100n) *c4*(x-2)^(3m)

Answer 5

hm this way doesnt work, there can be no possible poylnomial of this form, for integers

Answer 6

if this existed for integers then ud get remainders 2 and3 out of these divisions

Answer 7

remainred 2 and 1* so it shouldnt be possible this way