By what factor does the centripetal force change when you, a) twice the mass b) twice the speed c) twice the length d) twice the mass, twice the speed, and twice the distance all at the same time
@abb0t
@sshayer
@jhonyy9
I think a,b,c is 4 and d is 64.
\[centripetal~force =\frac{ mv^2 }{ r }\] a. when the mass is doubled ,force is doubled. b. when speed is doubled force is 2^2 i.e., 4 times the original force. c.twice the length ,centripetal force becomes half the original
d.\[f=\frac{ 2m \left( 2v \right)^2 }{ 2r }=4\frac{ mv^2 }{ r }=4* original force.\]
thanks, could you help with one more question? @sshayer
sure, i will try if i could.
Megan rides a horse at the outer edge of a merry-go-round. She is located 6 m from the central axis and is a bit frightened of the speed. So her parents place her on a horse 3 m from the axis. While on the inner horse, how will her linear speed compare with her speed on the outer horse?
@3mar
@AaronAndyson
plz post ur problem again in main page. not in a comment
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