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Mathematics 19 Online
OpenStudy (venomblast):

Help. See attahchment

OpenStudy (venomblast):

OpenStudy (venomblast):

I know for letter a it no invertible. I need help with 5b 5c 5d 5e

OpenStudy (venomblast):

@pooja195

OpenStudy (venomblast):

@pooja195

pooja195 (pooja195):

@518nad

pooja195 (pooja195):

@Nnesha

OpenStudy (caozeyuan):

for b you need to calculate the derative of each basis

OpenStudy (caozeyuan):

1'=0,x'=1, x^2'=2x, x^3'=3x^2

OpenStudy (caozeyuan):

\[\left[\begin{matrix}0 & 1 & 0 & 0 \\ 0 & 0 &2& 0 \\ 0 & 0 & 0 & 3 \\ 0 & 0 &0 &0\end{matrix}\right]\]

OpenStudy (caozeyuan):

this is you matrix h1

OpenStudy (caozeyuan):

h2 is h1*h1

OpenStudy (venomblast):

omg thanks. but what do I do when a question says represent a matrix on the basis...

OpenStudy (venomblast):

with question d, do you add the two matric with h_1 and 2*h_2?

OpenStudy (venomblast):

@caozeyuan

OpenStudy (caozeyuan):

yes, and for e you need to express the derivative of each basis as a column vector, then the matrix whose column are those columnn vectors is the h1 under this basis

OpenStudy (caozeyuan):

e.g 1 is (1,0,0,0) and 1'=0 which is (0,0,0,0)

OpenStudy (caozeyuan):

so (0,0,0,0) is the left most column of your h1

OpenStudy (caozeyuan):

(1+x)'=1 so your second to the left one is (1,0,0,0)

OpenStudy (caozeyuan):

so after you took the derivatives of the basis they give you in e, write down the coefficents of the derivative as a column vector with the first componenet being contant term and last componet being the coeff for x^3

OpenStudy (venomblast):

Ok but how do I know which number to plug in. Going back to question d, I need to add the two representation together or the function?

OpenStudy (caozeyuan):

h2 is just h1*h1, and I've already wirttern h1 as a matrix which you can just do the matrix multiplication to get h2

OpenStudy (caozeyuan):

then you have a matrix which is 2*h1 and you add these two together to get the answer

OpenStudy (venomblast):

2h1 is not the same as h1×h1

OpenStudy (caozeyuan):

but h2 is

OpenStudy (caozeyuan):

you also need to add 2*h1 to the h2 you just calculated from h1*h1

OpenStudy (venomblast):

Ok I got it. How do represent on question e?

OpenStudy (venomblast):

@caozeyuan

OpenStudy (caozeyuan):

hang on a second, eating dinner right now be back in half a hour

OpenStudy (venomblast):

!!! I got vector 1000,1100,1110,1111

OpenStudy (caozeyuan):

yes, and now you have to deffientiate each basis to get the basis after the transformation

OpenStudy (caozeyuan):

for example, 1000 becomes 0000 becuase 1'=0

OpenStudy (venomblast):

Wait I thought the question ask to just represent

OpenStudy (venomblast):

Will I get 0000,0100,0120,0123 ?

OpenStudy (caozeyuan):

Yes you need to represent the transformtion, nott the basis of your original vector space

OpenStudy (caozeyuan):

\[T:V \rightarrow W\]

OpenStudy (caozeyuan):

this linear transformation maps the basis of V to basis of W

OpenStudy (caozeyuan):

your basis in V is given, tey are 1000, 1100, 1110, 1111

OpenStudy (caozeyuan):

and you can obtain basis in W by computing the derivative, they are 0000, 1000, 1200, 1230

OpenStudy (caozeyuan):

so 0 1 1 1 0 0 2 2 0 0 0 3 0 0 0 0

OpenStudy (caozeyuan):

this is your matrix representation of T

OpenStudy (caozeyuan):

notice if you let T act on each basis vector in V it returns the corresponding basis vector in W

OpenStudy (venomblast):

But when you take the derivative you would get 0100 in the second column

OpenStudy (caozeyuan):

I just relized your calculation of basis of W is wrong

OpenStudy (caozeyuan):

no, you get 1000

OpenStudy (caozeyuan):

this is your (1+x)' which js just 1, hence your write 1000

OpenStudy (venomblast):

What the answer then?

OpenStudy (caozeyuan):

0 1 1 1 0 0 2 2 0 0 0 3 0 0 0 0

OpenStudy (venomblast):

Show me how you got that

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