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Physics 64 Online
OpenStudy (sourav.mondal96):

Give me a complete explanation of Characteristic X-Rays.

OpenStudy (osprey):

This isn't by any means "complete", but ... electrons are accelerated towards a metal target. when they hit the target they are decelerated rapidly - "bremsstrahlung" or braking radiation. any charged particle being accelerated or decelerated ("non inertial" in Relativity terms) emits electromagnetic radiation. on a graph, the bresstrahlung (german word) is the background X radiation. The electrons with the right energies can also promote electrons in the target metal into excited states. When these electrons de excite they emit radiation. The characteristic spikes in the graph whose overall curve is the bremsstrahlung. The various energy states in the target metal are characteristic of the target. Hope this is right.

OpenStudy (shamim):

x rays is an electromagnetic wave

OpenStudy (shamim):

visible light is also an electromagnetic wave

OpenStudy (shamim):

but frequency of an x ray is higher than the frequency of visible light

OpenStudy (shamim):

so x ray has higher energy than visible light

OpenStudy (shamim):

wavelength of x ray is lower than that of visible light

OpenStudy (shamim):

anyway can u tell me the velocity of x ray?!

likeabossssssss (likeabossssssss):

\(\Huge\color{#EB00FF}{\text{WELCOME}}\) \(\Huge\color{blue}{\text{TO}}\) \(\Huge\color{green}{\text{OPEN}}\)\(\Huge\color{purple }{\text{ STUDY!!!!!!!!!!!}}\) \(\Huge\heartsuit\) what do u think it is

OpenStudy (osprey):

@shamim The velocity of x-rays IN A VACUUM is 300, 000, 000 metres per second. This is for ANY electromagnetic radiation - infrared to ultraviolet, to gamma rays to radio waves etc. (In a medium such as a dielectric, the speed of light will generally be LOWER - refractive index). It does not matter how fast a light source or an X ray source is moving, the speed of the x-rays is always the same (one of Einstein's postulates of special relativity).

OpenStudy (irishboy123):

+1 @osprey!

OpenStudy (shamim):

anyway I was asking the question to the asker

OpenStudy (shamim):

however thank u @osprey

OpenStudy (osprey):

I get muddled

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