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Mathematics 9 Online
OpenStudy (sleepyjess):

Quick integral problem below

OpenStudy (sleepyjess):

\[\int\limits 4/3t~ dt\]

OpenStudy (error1603):

Sorry I'm not that smart

OpenStudy (sleepyjess):

Could I change it to \(\dfrac43 *\dfrac 1t\), then the integral would be \(\dfrac43 ln|t| + c\)?

OpenStudy (sleepyjess):

@zepdrix @steve816

OpenStudy (destinyyyy):

That answer looks correct to me.. But I dont want to give you an absolute yes

OpenStudy (irishboy123):

if it was \[\int\limits \dfrac{4}{3t}~ dt\] ie \[= \dfrac{4}{3} \int\limits \dfrac{1}{t}~ dt\] ....then yes

OpenStudy (steve816):

4/3 is just the constant, so you are just integrating 1/t. Your answer is correct btw!

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