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Quick integral problem below
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\[\int\limits 4/3t~ dt\]
Sorry I'm not that smart
Could I change it to \(\dfrac43 *\dfrac 1t\), then the integral would be \(\dfrac43 ln|t| + c\)?
@zepdrix @steve816
That answer looks correct to me.. But I dont want to give you an absolute yes
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if it was \[\int\limits \dfrac{4}{3t}~ dt\] ie \[= \dfrac{4}{3} \int\limits \dfrac{1}{t}~ dt\] ....then yes
4/3 is just the constant, so you are just integrating 1/t. Your answer is correct btw!
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