Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (bluemoon1):

Can any moderators help me?

OpenStudy (bluemoon1):

Find the slope of a line perpendicular to each given line. 2x+5y=-15 Y=-3/2x+1

OpenStudy (bluemoon1):

@miracrown are you good at math?

OpenStudy (bluemoon1):

@pooja195

OpenStudy (sarahhanish):

mods arent alwats good at math they are here to make sure we are behaving

OpenStudy (sarahhanish):

always*

OpenStudy (solomonzelman):

In general, when you have a line in a form \(\color{black}{y=mx+b}\), then the slope of a(ny) line perpendicular to the line above is \(\color{black}{-1/m}\).

OpenStudy (solomonzelman):

Actually, perhaps as a coincidence, but most of them are good at math:)

OpenStudy (bluemoon1):

Oh okay. Umm how do I go on

OpenStudy (solomonzelman):

Well, try to re-write each line in the same format (like \(\color{black}{y=mx+b}\)).

OpenStudy (bluemoon1):

How do I do that. Sorry I'm not good at math

OpenStudy (bluemoon1):

5y= -2x+15 y= -2x/5+15 y= -2x/5+3?

OpenStudy (solomonzelman):

Example: \(\color{black}{4y+6x=9}\) First we re-write using algebraic manipulations. \(\color{black}{4y+6x\color{red}{-6x}=\color{red}{-6x}+9}\) \(\color{black}{4y=-6x+9}\) \(\color{black}{\color{red}{(}4y\color{red}{)\div 4}=\color{red}{(}-6x+9\color{red}{)\div 4}}\) \(\color{black}{y=-\frac{3}{2}x+\frac{9}{4}}\) So, the slope is -3/2. Thus, a perpendicular line will have slope of 1 divided by that. In other words, \(\color{black}{\frac{1}{-\frac{3}{2}}=-1\div \frac{3}{2}=-1\times \frac{2}{3}=\frac{-2}{3}}\).

OpenStudy (bluemoon1):

Is my answer above right?

OpenStudy (solomonzelman):

You rearranged it correctly. In other words, you solved for y correctly.

OpenStudy (bluemoon1):

Okay. What do I do next?

OpenStudy (solomonzelman):

For any line \(y=mx+b\), the slope is \(m\). So in your case what is the slope?

OpenStudy (bluemoon1):

I don't know

OpenStudy (solomonzelman):

y= -2x/5+3 is your equation. (You solved for y correctly, good job on that!)

OpenStudy (solomonzelman):

Given what I said just now (which is a rule for any line), what is the slope of your line?

OpenStudy (bluemoon1):

-2/5?

OpenStudy (bluemoon1):

@solomonZelman

OpenStudy (solomonzelman):

yes, correct.

OpenStudy (solomonzelman):

So, since your slope is -2/5, the slope of a perpendicular line would be 1 divided by that.

OpenStudy (solomonzelman):

In other words, your slope is: \(\large \bf \frac{~~~-1~~~}{\frac{-2}{5}}=-1 \div \frac{-2}{5}=\)

OpenStudy (bluemoon1):

It would still be the same answer right?

OpenStudy (solomonzelman):

all that remains to you is to simply.

OpenStudy (solomonzelman):

The same as what? You haven't posted any answer.

OpenStudy (solomonzelman):

You posted the rearrangement where you solved your equation for y, which is correct, and identified the slope.

OpenStudy (bluemoon1):

It would still be -2/5? If you divided it by 1

OpenStudy (solomonzelman):

no, it wouldn't

OpenStudy (mathmate):

@BlueMoon1 Actually both mods are good at math, but @sarahhanish 's comments remain valid.

OpenStudy (sarahhanish):

cool dont add me on this no more :0

OpenStudy (solomonzelman):

Can you finish dividing? \(\large \bf \frac{~~~-1~~~}{\frac{-2}{5}}=-1 \div \frac{-2}{5}=\) I will give you a kicker. The rule is (if \(a\) and \(b\) are both not \(0\)) \(\large \bf x\div \frac{a}{b}=x\times \frac{b}{a}\)

OpenStudy (bluemoon1):

So no solution?

OpenStudy (bluemoon1):

Oh my goodness I don't know.

OpenStudy (solomonzelman):

Proceeding with the rule I just gave above you have: \(\large -1 \div \frac{-2}{5}=-1 \times \frac{5}{-2}\)

OpenStudy (solomonzelman):

Can you go from there?

OpenStudy (bluemoon1):

That's 5/2

OpenStudy (solomonzelman):

Yup, exactly!

OpenStudy (bluemoon1):

So that's the answer?

OpenStudy (solomonzelman):

Yes, that is the answer.

OpenStudy (solomonzelman):

(The slope of any line which is perpendicular to the line expressed in the question.)

OpenStudy (bluemoon1):

Thanks! I also need help on the other one. If you could do that you would be a lifesaver

OpenStudy (solomonzelman):

If I have time ... I am bouncing here and there right now (kinda). Will see.

OpenStudy (solomonzelman):

I am pretty sure there are many people who know math better than me, and are also better at explaining it. (Again, will see....) yw

OpenStudy (bluemoon1):

Thanks. I have this whole worksheet that I'm confused on so it really helps thank you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!