An AM radio station broadcasts at 1440 kHz, and its FM partner broadcasts at 100.5 MHz. Calculate and compare the energy of photons emitted by these radio stations.
AM:
FM:
EFM / EAM:
Thank you so much!

Question

An AM radio station broadcasts at 1440 kHz, and its FM partner broadcasts at 100.5 MHz. Calculate and compare the energy of photons emitted by these radio stations.
AM:
FM:
EFM / EAM:
Thank you so much!

aaronq · Answer

The formula you need to use is $E_{photon}=h*\nu $

where h is plancks constant ($6.626 × 10^{-34}~ m^2 kg / s$), and $\nu$ is frequency (in Hz)

You also need to convert kHz and MHz to Hz

archaists · Answer

Okay, so I first convert?

archaists · Answer

1440000 hertz and 100500000 hertz?
6.626e−34 * x
AM: -48959982?
FM: -3.41699998e9?

archaists · Answer

No, it says those are wrong.

aaronq · Answer

for AM i got 9.54144e-28 and for FM i got 6.65913e-26

aaronq · Answer

i think you're multiplying incorrectly, since you're getting negative values.

archaists · Answer

Oh okay, thank you. Let me try those and if they are correct I will go back and check my multiplication.

archaists · Answer

They are correct, thank you! I went back and I must have messed up when multiplying with the exponent. Do you know how to find EFM / EAM or what that even is?

aaronq · Answer

No problem. I think they want a ratio of the energies

$\sf  \dfrac{energy~of~FM ~photon}{energy~of~AM~photon}$

archaists · Answer

Okay, let me try that. (6.659e-26)/(9.541e-28)

aaronq · Answer

That should yield the right answer

archaists · Answer

I got it, thank you very much!

aaronq · Answer

okay great! no problem