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Mathematics 8 Online
OpenStudy (sleepyjess):

Integrals :)

OpenStudy (sleepyjess):

\[\int\limits 8(x+x^2)^{-1}~dx\]

OpenStudy (sleepyjess):

Would I distribute the 8 first?

Nnesha (nnesha):

\[\int\limits_{ }^{ } \frac{8}{x(1+x^2)} dx \]

OpenStudy (johnweldon1993):

I would just move the 8 out of the integral :) It's just a constant

OpenStudy (amorfide):

wouldn't that be x(1+x) on the bottem nnesha

OpenStudy (sleepyjess):

Whoops, that was supposed to be 1+x^2

OpenStudy (solomonzelman):

\(\displaystyle \int \frac{8}{x^2+1} dx\). Trig sub.

OpenStudy (solomonzelman):

or just recon the derivative of what may the integrand be?

OpenStudy (solomonzelman):

(You have done the derivatives of inverse trig functions, haven't ya?)

OpenStudy (sleepyjess):

Yes, we've done inverse sine, tangent and secant

OpenStudy (solomonzelman):

Yes ... more is not requered.

OpenStudy (sleepyjess):

Oohhh, I think I see, it would be 8\(tan^{-1}x + c\)?

OpenStudy (solomonzelman):

Do you remember the inverse derivative of \(\arcsin(x)\), \({\rm arcsec}(x)\), and \(\arctan(x)\)?

OpenStudy (solomonzelman):

did I just say INVERSE DERIVATIVE ?? OMG ... Just derivative (not inverse derivative)

OpenStudy (solomonzelman):

yes, you are thinking correctly:)

OpenStudy (sleepyjess):

We haven't done any of those 3...

OpenStudy (solomonzelman):

Though, if you want to actually solve it, as opposed to realizing the derivative, you may choose to ask for more assistance. (If you learned trig sub, I would advise that, if not, don't worry right now, you will cover it later.)

OpenStudy (sleepyjess):

We haven't gotten into that yet, just started integrals today :)

OpenStudy (solomonzelman):

Oh today ... you are getting tuned in very quickly then. Keep it up!

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