Find Lim( (sin3x/x) -1) as x --> 0
Hey, welcome to OpenStudy! :) This is our problem? \[\large\rm \lim_{x\to0}~\frac{\sin(3x)}{x}-1\]
Yea that is the problem! My answer was 2 but it was wrong so i dont know what to do.
This is a special limit identity that you learn early on in Calculus,\[\large\rm \lim_{y\to0}\frac{\sin(\color{orangered}{y})}{\color{orangered}{y}}\quad=\quad 1\]The important thing for this identity is that the angle matches the denominator.
So for your problem, you need to find a fancy way to get a 3 in the denominator. You want to create a 3x in the denominator so it matches the argument of the sine.
Wait... you ended up with 2? That shouldn't be wrong D: Hmm
Just for confirmation: https://www.wolframalpha.com/input/?i=limit+as+x+approaches+0+of+(sin(3x))%2Fx-1
Yea thats what i was thinking. My professor probably made a mistake than.
Ya, weird :)
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