Question

HELP ASAP

Answer 1

@3mar

Answer 2

@iwanttogotostanford
still need help?

Answer 3

Hint:
Divide both numerator and denominator by the largest power of x, i.e: \(x^3\)
You would write it like that:
\[\Large \frac{ -8x^2+5x }{ -8x^3+7x^2-5x-4 }=\frac{ x^3[-\frac{ 8x^2}{ x^3 }+\frac{ 5x }{ x^3 }] }{ x^3[-\frac{ 8x^3 }{ x^3 }+\frac{ 7x^2 }{ x^3 }-\frac{ 5x }{ x^3 }-\frac{ 4 }{ x^3 }]}\]

Answer 4

\[\large=\lim_{x \rightarrow \infty}\frac{-\frac{ 8 }{ x }-\frac{ 5 }{ x^2 } }{ -8+\frac{ 7 }{ x }-\frac{ 5 }{ x^2 }-\frac{ 4 }{ x^3 } }=\Large \frac{ 0-0 }{ -8+0-0-0 }=\color{RebeccaPurple }{\frac{ 0 }{ -8 }}=\Huge\color{DarkSlateBlue }{0}\]

Answer 5

Thank you for the medal!