Three consecutive even integers have a sum of
48. Find the integers.

Question

Three consecutive even integers have a sum of 
48. Find the integers.

likeabossssssss · Answer

what do u think it is?

ebonyserrano · Answer

I got 6,7,8

ebonyserrano · Answer

@likeabossssssss  thanks for the help

ebonyserrano · Answer

it says it's incorrect

ebonyserrano · Answer

it said it would be 14,16, and 18

563blackghost · Answer

We know three consecutive numbers equal 48, due to the fact that the number are even we would go up by multiples of 2.

$\huge\bf{(n)+(n+2)+(n+4)=48}$

Combine Like terms.

$\huge\bf{3n+6=48}$

Subtract 6 from both sides.

$\huge\bf{3n=42}$

Divide by 3.

$\huge\bf{n=14}$

Now input 14.

$\huge\bf{(14)=14}$

$\huge\bf{14+2=16}$

$\huge\bf{14+4=18}$

$\huge\bf\color{red}{14,16,18}$

That should be your answer @Ebonyserrano

563blackghost · Answer

At least I think thats how you do it...do you agree @KJSaif ?