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Mathematics 6 Online
OpenStudy (devonhoward15):

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OpenStudy (devonhoward15):

OpenStudy (devonhoward15):

@Vijeya3

OpenStudy (steve816):

First step: Get the equation into slope-intercept form! y =mx+b Step 2: remember that parallel lines will have the same slope, and perpendicular lines will have the opposite reciprocal of the slope.

OpenStudy (kittiwitti1):

slope intercept form...\(y=mx+b\) where \(m\) is the slope, and \(b\) is the y-intercept (which is where \(y=0\) on the graph).

OpenStudy (devonhoward15):

you guys are so good at math lol... i suck haha... i wouldnt be good at math if it slapped me in the face lol

OpenStudy (kittiwitti1):

basically isolate the \(y\) variable and you have the slope intercept form. anything that is perpendicular to a line means you have the negative reciprocal of the slope of the line.

OpenStudy (kittiwitti1):

if you have normal line with slope \(a\)... then your equation is\[y_{1}=(a)x+b\]now we find the negative reciprocal, which is \(\large{-\frac{1}{a}}\)... so\[y_{2}=\left(-\frac{1}{a}\right)x+b\]

OpenStudy (kittiwitti1):

does this make sense?

OpenStudy (devonhoward15):

nope... @563blackghost

OpenStudy (devonhoward15):

@dumbcow @AloneS

OpenStudy (kittiwitti1):

what part of it does not make sense?

OpenStudy (kittiwitti1):

would you like me to start over from the beginning?

OpenStudy (devonhoward15):

math doesnt make sense... no i good... i got my friend coming thanks though

OpenStudy (devonhoward15):

@Will.H

OpenStudy (kittiwitti1):

no, I am a tutor and it's my duty to finish what I start :P now tell me where you're confused

OpenStudy (devonhoward15):

i got my personal tutor mate :)

OpenStudy (devonhoward15):

and im confused with math lol... it sucks

OpenStudy (kittiwitti1):

you have the original line \(-x+4y=20\), yes? this needs to be in the slope intercept form of \(y=mx+b\) to understand the rest. so you need to isolate the \(y\).\[-x+4y=20\]\[4y=x+20\]\[\frac{\cancel{4}y}{\cancel{4}}=\frac{x}{4}+\frac{20}{4}\]\(\large{y=\frac{x}{4}+5}\) or \(\large{y=\frac{1}{4}x+5}\), making the slope \(\large{\frac{1}{4}}\)

OpenStudy (devonhoward15):

so the slope for the original line is 1/4

OpenStudy (will.h):

Main equation is -X + 4y = 20 Set it in slope form so that we get to recognize the slope. 4y = x + 20 Y = 1/4)x + 5 Slope is 1/4 whichever equation share the same slope it would be parallel to that. Whichever gets a product of -1 would be perpendicular. Let's see the 1st one -X + 4y = 8 4y = x + 8 Y = 1/4)x + 2 So this is parallel The 2nd is 4x + y = -1 Y = -4x -1 -4 * 1/4 = -1. Therefore perpendicular The 3rd Is neither The 4th is perpendicular

OpenStudy (kittiwitti1):

yup ☺ now if you want to find the slope of a \(perpendicular\) line, then you take the negative reciprocal of the slope, which is basically -1 divided by the original slope. the slope of the original line is a fraction \(\large{\frac{1}{4}}\), so if you divide -1 by that you get \[-1\div\frac{1}{4}\rightarrow-1\times\frac{4}{1}=\frac{-4}{1}=-4\]

OpenStudy (kittiwitti1):

so in the perpendicular line you would have something like this:\[y=-4x+b\]

OpenStudy (kittiwitti1):

(you might have to convert all those answer choices to \(y=mx+b\) form though. remember to keep the \(y\) by itself!)

OpenStudy (will.h):

Good work kitti

OpenStudy (kittiwitti1):

thanks @Will.H

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