Question

I NEED HELP PLEASE HELP
Triangle STU is located at S (2, 1), T (2, 3), and U (0, −1). The triangle is then transformed using the rule (x−4, y+3) to form the image S'T'U'. What are the new coordinates of S', T', and U'?

Answer 1

let's start with one of the points \(S\), with coordinates \((2,1)\)
now the transformation wants you to apply \((x-4,y+3)\) or "left 4 units, up 3 units" ...so you get:\[(2-4,1+3)\rightarrow(-2,4)\]

Answer 2

basically you have three points, each with their own coordinate pair of \((x_{1},y_{1})\). you need to plug the x and y coordinates into their respective variables of \(x\) and \(y\) in the transformation \((x-4,y+3)\) and you will get your new image of \(S'T'U'\).

Answer 3

\((\color{red}{x_{1},y_{1}})\longleftrightarrow(\color{red}{x}-4,\color{red}{y}+3)\)

Answer 4

Yes

Answer 5

you got it?

Answer 6

Im still working on it

Answer 7

@steve816

Answer 8

HELP

Answer 9

I'm not so good with math of any kind im better at reading and stuff

Answer 10

it's okay, take your time :)

Answer 11

For point S, the new coordinates would be 2-4 and 1+3 S'(-2, 4)
for point T, the new coordinates would be 2-4 and 3+3 T' (-2, 6)

Answer 12

is that right O__O

Answer 13

sorry, was distracted by another question lol

Answer 14

it's fine tyt :)

Answer 15

you got them right ☺

Answer 16

now what is \(U'\)?

Answer 17

Umm

Answer 18

i'm not sure