Question

@Will.H

Answer 1

@W

Answer 2

@Will.H

Answer 3

he's helping someone else with slope right now. what's your question?

Answer 4

\(2x+3y=3\) is your equation.
to get in slope form \(y=mx+b\) you make sure you have the \(y\) by itself...
... you get \[y=-\frac{2}{3}x+1\]

Answer 5

so your ORIGINAL slope is -2/3.

Answer 6

now they want a PARALLEL line, which means you have exactly the same slope. so don't worry about that.
currently we have the parallel line as:\[y=-\frac{2}{3}x+b\]

they say the line passes through the point \((3,-4)\) so that means \(\color{red}{x=3}\) and \(\color{blue}{y=-4}\)... put this in the equation of the parallel line...\[\color{blue}{-4}=-\frac{2}{3}(\color{red}{3})+b\]

Answer 7

make sense?

Answer 8

2x + 3y = 3
Find slope
3y = -2x + 3
Y = -2/3)x + 1

Slope is -2/3. And since they said "parallel " then the slope of the other line would also be -2/3

That passes through (3,-4)
Now we use
Y - Y1 = m(x-x1)

Substitute
Y - (-4) = -2/3(x - 3)
Y + 4 = -2/3)x + 2
Y = -2/3)x -2

Answer 9

so anwser is y=-2/3(x-2)

Answer 10

Yeah I hate to explain for too long XD

Answer 11

No Devon

Answer 12

Y = (-2/3)x - 2

Answer 13

how about you go off of what I said... solve for \(b\) and then put it back in the equation...\[y=-\frac{2}{3}x+b\]

Answer 14

if you do it right you should get \(b=-2\), and then you'd have the same result as will's explanation.