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Mathematics 5 Online
OpenStudy (sissyedgar):

Question in Comments. Thanks. ♥

OpenStudy (sissyedgar):

@mathmate

OpenStudy (sissyedgar):

@AloneS

OpenStudy (sooobored):

exponential x^n type of relation

OpenStudy (sooobored):

if it helps, think of it like a geometric sequence

OpenStudy (sissyedgar):

...Sorry I don't think I'e learned about whatever that is yet.....

OpenStudy (sissyedgar):

@3mar

OpenStudy (sooobored):

does this look familar \[B_n= B_0 *x^n\]n where Bn is the total number of books at nth month and n is the month

OpenStudy (sissyedgar):

All I know is that I think the formula is.... \[A=Pe ^{rt}\]

OpenStudy (3mar):

You are welcome! I will not be late for any help. Not because I don't prefer you picture I will not help you. Absolutely not! That is not my own business, but it is yours. I was just saying a word of advice to my sister, take it or leave it!

OpenStudy (sooobored):

oh... you use e^rt that makes it slightly harder but essentially, find r with the given information

OpenStudy (sooobored):

we look at the initial month, which we consider as t=0 and A= 80 we can get P

OpenStudy (sooobored):

we look at the first month, t=1 and A=100 since we know P now we can determine r

OpenStudy (sooobored):

then you should have your exponential equation

OpenStudy (3mar):

\[\Huge\color{Chocolate }{A=Pe ^{rt}}\] You can use the first point (0,80) to get the value of \(P\) Can you share your works/steps, please?

OpenStudy (3mar):

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