Help! My Algebra 1 teacher handed out a hand written assignment. I need some help on how to solve this equation: 5x – 5 >= 10 or -3x + 1 >= 13 She says I have to show all of my work. I'm not that good on solving these equations. It would help me in the second part of the assignment also. I need to graph the inequality in the second part *if you notice answers below, don't mind them. Their from a different question. I'm unsure of how to delete previous questions and ask new ones other then editing them and asking a new one* Can someone please help me? This is due by midnight
I'll help you with the first one but you post each question per post oki?
oki!
A. x<= -10 First one^
Multiply each sides by \(2\), than simpltiply \(5\) by \(2\) to \(10\) \[\ 10≤−x\] And multiply each side by negative one \[\ −10≥x\] Than switch those side, \(x≤−10\) or as \(x<= -10\)
*Simplify >_>
Here. This file has both the equation and the graph. If your able to help, please do.
The first half has already been helped with, unless you still don't understand it. The second half of the same question was over looked: \[-3x+1\ge13\] Would you like help with that?
Yes please
You must isolate x first. I'll do the first step. \[-3x+1\ge13\] \[-3x \ge 12\] Could you try to do the rest?
I could try. But I'm not really sure what else to do in order to try
You want x as one unit. You want x as x (it looks the same as 1x), not -3x.
Would I want to divide both sides by -3 (if I have to divide) or one side by -3 and the other by positive 3?
Both sides by -3. You will also flip the sign because the sign flips when either multiplying or dividing
Being that -3 cancels itself out and i get -4 when i divide -3 by 12, how would I set up the inequality?
Applying the rules (sign changing, x isolated...) it would look like \[x \le-4\] Did you understand when the others helped you with the 5x-5>= 10?
Not really no. This concept is a bit confusing for me
Ok this one looks easier. Add five to isolate x \[5x-5\ge10\] changes into \[5x \ge15\]
Make sense?
Yep
The last step in turning 5x into x is to...?
Cancel out 5? I'm honestly not really sure
Divide all sides by 5. The end result would be...?
X ≥ 3?
Yes!
The second half is visually putting the two inequalities together
How exactly would I do that?
By taking each inequality and graphing it on a number line. Let's take a finished one. \[x \ge5\] and plotting it on the line. The line should look like this: |dw:1479430649688:dw|
The picture looks bad, but each tick represents a number with each side extending to infinity
\[x \ge5\] would start on exactly 5 and stretch infinity positively. The line underneath the > means equal, so the symbol entirely would 'exactly 'x' (whatever number that might be) and above.' Is 6 bigger than 5? Yes, so we say \[6\ge5\] Understand?
Yep
Then the other one would extend in the opposite direction correct?
Yes. \[x \le-4\] would strech the other way. You'll be seeing 'and' and 'or' a lot of times. Here are the rules. And: the x is in between the two inequalities Or: the x is either in one inequality or the other but not both.
In this case, it's an 'or' so the unknown x is in one inequality. This will show a gap REMEMBER: In inequalities there is no definite number for x hence the IN in inequality. How would the number line look like with the inequalities shown?
I don't think that the inequalities would be connected on the graph. So one would be infinitely positive and the other infinitely negative
If the X was in between both or 'and', then they'd be connected. Being that 'or is in there, then they'd go in the opposite direction of each other
My hint with remembering with the direction inequalities is simple: the arrow points the direction it's headed. This applies to all inequality signs. \[> meaning \rightarrow on number line\] \[< meaning \leftarrow on number line\]
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