Question

math = physics =fun

Answer 1

An arrow fired horizontally at 41 m/s travels 23 m horizontally before it hits
the ground. From what height was it fired?

Answer 2

can someone plz help

Answer 3

Me!

Answer 4

yea go ahead

Answer 5

We are learning this stuff right now too :( It is sooo hard.

Answer 6

I'll try to help though.

Answer 7

ok cool

Answer 8

First, we can calculate the time the arrow is in the air by using the equation

Answer 9

is that the formula

Answer 10

Since the acceleration is constant for the horizontal component, the acceleration is 0. Therefore solve for t on this equation
23=41t

Answer 11

41/23

Answer 12

Nope, it would be 23/41

Answer 13

oh yea true

Answer 14

0.6

Answer 15

t = 0.561

Answer 16

we found the time so now lets find the height

Answer 17

Yup! Let's find the height!

Answer 18

The initial velocity of the vertical component is 0, do you follow?

Answer 19

do we use d=1/2gt^2

Answer 20

Since the initial velocity is 0, you would use that equation! Exactly :)

Answer 21

\[\huge d=\frac{ 1 }{ 2 }9.8(0.561)^2\]

Answer 22

d=4.9(.56)^2

Answer 23

What do you get for distance?

Answer 24

1.5m

Answer 25

HAHA LOL

Answer 26

Thank you

Answer 27

No problem!