Question

help me plz someone?

Answer 1

Use the distance formula to find the length and the width!

Answer 2

In case you don't got it memorized.

Answer 3

@563blackghost I see you finally figured out the magic!!!!! The most useful thing ever!!!!!!!!!!!!

Answer 4

Simply find the distance between `(-2,3) and (2,-3)` and `(-2,3) and (1,5)` and once each are found multiply :)

Answer 5

Yes I did @steve816 :)

Answer 6

\(\huge\bf{d=\sqrt{(-3-3)^{2}+(2+2)^{2}}}\)

\(\huge\bf{d=\sqrt{(5-3)^{2} + (1+2)^{2}}}\)

Answer 7

Find each and then multiply.

Answer 8

kk wait

Answer 9

i got 22 and 17?

Answer 10

Not quite.

First simplify parathesis.

\(\huge\bf{d=\sqrt{(-6)^{2}+(4)^{2}}}\)

Apply power then add the two. `Note: -a^n equals a^n, so -6^2 equals 6^2`

\(\huge\bf{d=\sqrt{52}}\)

Factor out prime, 52 is made from 2^3 and 13.

\(\huge\bf{d=2\sqrt{13}}\)

Answer 11

For the second one we follow a similar process.

\(\huge\bf{d=\sqrt{(2)^{2}+(3)^{2}}}\)

Simplify exponents and add.

\(\huge\bf{d=\sqrt{13}}\)

Answer 12

Now we multiply the two.

\(\huge\bf{2\sqrt {13} \times \sqrt {13} = \color{red}{area}}\)

Answer 13

Or to do this simplier we leave the first distance in its not simplified form.

\(\huge\bf{\sqrt{52} \times \sqrt{13} = \sqrt{52 \times 13} \rightarrow \sqrt{676}}\)

\(\huge\bf{\sqrt{676} = \color{red}{answer}}\)

Answer 14

Do you have a cal to simplify \(\large\bf{\sqrt{676}}\) ?

Answer 15

Alternatively, can you factor 676 so that at least one of your factors is a perfect square?

Supposing that that perfect square were 36; the square root of that would be 6.