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Mathematics 19 Online
OpenStudy (18jonea):

Which statement is false about f(x) = ln x? It is increasing on its domain. It is unbounded. It is symmetric about the origin. It has a vertical asymptote. @3mar

OpenStudy (3mar):

Can you plot it and see?

OpenStudy (18jonea):

just a secpnd

OpenStudy (18jonea):

OpenStudy (18jonea):

i think the answer is d

OpenStudy (18jonea):

@3mar

OpenStudy (3mar):

Do you think that "It has a vertical asymptote" is not correct?

OpenStudy (18jonea):

wait no it does

OpenStudy (18jonea):

right?

OpenStudy (18jonea):

@3mar

OpenStudy (3mar):

yes it does not!

OpenStudy (18jonea):

ok so d would be my answer

OpenStudy (3mar):

I told you that D is not correct. f(x)=ln(x) does already have a vertical asymptote (the y-axis or at x=0)

OpenStudy (18jonea):

you said it does not have

OpenStudy (18jonea):

it is not symmetric to the origin

OpenStudy (18jonea):

@3mar

OpenStudy (3mar):

\[\Huge\color{red}\checkmark\] That is it!

OpenStudy (18jonea):

i have 4 more is that ok?

OpenStudy (3mar):

but 5 min please

OpenStudy (18jonea):

ok i will post and then whenever you are available

OpenStudy (3mar):

Ok Thank you for the medal!

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