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Which statement is false about f(x) = ln x? It is increasing on its domain. It is unbounded. It is symmetric about the origin. It has a vertical asymptote. @3mar
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Can you plot it and see?
just a secpnd
i think the answer is d
@3mar
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Do you think that "It has a vertical asymptote" is not correct?
wait no it does
right?
@3mar
yes it does not!
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ok so d would be my answer
I told you that D is not correct. f(x)=ln(x) does already have a vertical asymptote (the y-axis or at x=0)
you said it does not have
it is not symmetric to the origin
@3mar
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\[\Huge\color{red}\checkmark\] That is it!
i have 4 more is that ok?
but 5 min please
ok i will post and then whenever you are available
Ok Thank you for the medal!
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