Write the standard form of the line that is parallel to 2x + 3y = 4 and passes through the point (1, -4)
2x + 3y = 4 is already in "standard form of the equation of a straight line." So the new equation will look the same, EXCEPT that the constant will no longer be 4. Think: 2x + 3y = c Substitute the x- and y-coordinates of the given point into 2x + 3y = c; find c. Then write out the "standard form of the equation of a straight line" with your c substituted.
if you use the form y=mx+b, then you will want to convert 2x+3y=4, into the format y=mx+b so make y the subject 2x+3y=4 3y=-2x+4 |dw:1478877501394:dw| a line that is parallel to this, will have the same gradient. This is the only rule you need to know so using the form y=mx+b m is the slope, our slope is -2/3 and b is any constant translation so |dw:1478877548389:dw| hence, this line is parallel to the one you currently have, so to choose a specific line parallel, you can put any value of b that you want, whether b=2,3,5,6,7,8 but it can not be the same number that you had originally, which is 4 so |dw:1478877630923:dw|would work
Join our real-time social learning platform and learn together with your friends!