(09.04 MC)
A quadratic equation is shown below:

9x2 − 16x + 60 = 0

Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points)

Part B: Solve 4x2 + 8x − 5 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.

Question

(09.04 MC)
A quadratic equation is shown below:

9x2 − 16x + 60 = 0

Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points)

Part B: Solve 4x2 + 8x − 5 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.

kjsaif · Answer

Sorry for your question :(

gunsodo · Answer

Part A :
If complex numbers are not allowed in this problem,
the answers do not exist. Because (3x-8/3)^2>=0, always.
Which means 9x^2-16x+64/9>=0,
which means 9x^2-16x+60 cannot be 0.
If complex numbers are allowed,
use the formula x = $$\frac{ {-b \pm \sqrt{b^2-4ac}} }{ 2a}$$
and you'll be able to determine the complex roots, in the term of i.

Part B :
This one is pretty much more easier.
The equation could be simplify to the form of (2x+5)(2x-1)=0
The reason that I selected this solution is because the coefficients are related to each other. It can be easily simplified to 2 parenthesis.