Question

http://prntscr.com/d64op7

Answer 1

@steve816

Answer 2

Again, simply plug in 4 for n and you will have the answer!

Answer 3

I got 2/9 :/

Answer 4

I knew it! Ugh he left

Answer 5

Please...help

Answer 6

Probably had something to do. Just tag someone else when a tutor leaves. :-)

the 4th term in a sequence with \(n^{th}\) term would mean \(\color{red}{n=4}\):\[\large{a(\color{red}{4})=-6\left(-\frac{1}{3}\right)^{\color{red}{4}-1}}\]

Answer 7

So the 4th term is 4?

Answer 8

@kittiwitti1 You are leaving me too?

Answer 9

No, I am obviously still typing... Please don't assume things like that, it's very rude. ☻\[=-6\left(-\frac{1}{3}\right)^{3}=-6\left(-\frac{1}{3}\times-\frac{1}{3}\times-\frac{1}{3}\right)=-6\left(-\frac{1}{3^{3}}\right)=-6\times\left(-\frac{1}{27}\right)\]\[=\frac{-6}{-27}=\frac{6}{27}\]Dividing the numerator and denominator both by the common factor of 3...\[\frac{\cancel{6}^{2}}{\cancel{27}^{9}}=\frac{2}{9}\]

Answer 10

Therefore, yes; you are correct. 👌

Answer 11

Oh okay sorry I just didn't see u here that's why i thought u left me T_T
Thank you!

Answer 12

I got it wrong..again now I have to restart it

Answer 13

Oh shoot I put 4 why was 4 entered OMG im ss!

Answer 14

OS does tend to glitch like that...
You're very welcome; and if you don't see me while I'm still typing, then it probably kicked me out. Feel free to send me a PM if that happens :P

Answer 15

LOL, you worried me for a minute there... thought I'd put the wrong answer