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Geometry 14 Online
OpenStudy (mndean):

Please help! I will Fan and give medals to anyone who can help me!!- Figure ABCD is a rhombus with point A (3,-1). what rule would rotate the figure 270 degrees counterclockwise, and what coordinate would be the output for point A'?

HanAkoSolo (jamierox4ev3r):

What are your answer choices? @mndean

OpenStudy (mndean):

@Jamierox4es3r these are my options: a. (x,y)->(-y,-x); A' (1, -3) b. (x,y)->(-y,x); A' (1,3) c. (x,y)->(y,x); A' (-1,3) d. (x,y)->(y,-x); A' (-1,-3)

HanAkoSolo (jamierox4ev3r):

Okay. Do you have a picture of the problem as well that you could post :)

OpenStudy (mndean):

nope, it's just the problem with no picture, sorry.

OpenStudy (mndean):

@Jamierox4ev3r

HanAkoSolo (jamierox4ev3r):

fair enough! Alright, I'll give it my best shot

HanAkoSolo (jamierox4ev3r):

Have you tried drawing the parallelogram? The best way to do problems like this is to visualize it

OpenStudy (mndean):

I drew point A, that's as far as I can go :[

HanAkoSolo (jamierox4ev3r):

it doesn't matter what the rest of the rhombus looks like, as long as you know the point of rotation, which is usually at the origin!

OpenStudy (mndean):

oh okay, thanks you

HanAkoSolo (jamierox4ev3r):

of course!

HanAkoSolo (jamierox4ev3r):

Let me post something that I believe will help you ^.^

OpenStudy (mndean):

okay thanks

HanAkoSolo (jamierox4ev3r):

|dw:1478989237378:dw|

HanAkoSolo (jamierox4ev3r):

I know that's kind of hard to see, but the see the triangle in quandrant one? That is the orignal, and the other triangles are examples of counter clockwise rotations

OpenStudy (mndean):

awesome thank you! that helps a lot!

HanAkoSolo (jamierox4ev3r):

of course! :)

HanAkoSolo (jamierox4ev3r):

So based from this, can you tell me what you think the answer is?

OpenStudy (mndean):

No, :( I can't figure out how to create the 270 deg. rotation with my protractor.

OpenStudy (mndean):

@Jamierox4ev3r

HanAkoSolo (jamierox4ev3r):

it is pretty tough!

OpenStudy (mndean):

yes! D:

OpenStudy (seratul):

Why are you using a protractor?

OpenStudy (mndean):

@Seratul is there another way?

HanAkoSolo (jamierox4ev3r):

|dw:1478991001682:dw|

HanAkoSolo (jamierox4ev3r):

Note that a 270 degree counterclockwise rotation is also a 90 degree clockwise rotation

OpenStudy (seratul):

If you are graphing it, take the y for each coordinate and multiply by -1. Leave the x the same.

OpenStudy (seratul):

For example, (1,1) rotated counterclockwise for 270 degrees is (1,-1)

OpenStudy (mndean):

@Jamierox4ev3r wait! I think I got it! is the answer d?

OpenStudy (seratul):

Whoops, don't listen to what I said, I was thinking of reflection.

OpenStudy (mndean):

@Seratul lol it's okay thanks for trying! :)

OpenStudy (seratul):

But yea, the answer is d. :D

OpenStudy (mndean):

yahoo!!! thank you guys!

OpenStudy (mndean):

@Jamierox4ev3r

HanAkoSolo (jamierox4ev3r):

Yep, definitely D! Sorry, I went idle x.x

HanAkoSolo (jamierox4ev3r):

Rotation of 90º: (x,y) becomes (-y,x) Rotation of 180º: (x,y) becomes (-x,-y) Rotation of 270º: (x,y) becomes (y,-x) For future reference, see these rules!

HanAkoSolo (jamierox4ev3r):

**Keep in mind that rotations on a coordinate grid are considered to be counterclockwise, unless otherwise stated**

OpenStudy (mndean):

that's really helpful thank you!

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