HELP CALC.
The slope of the function \(\color{black}{ y=f(x) }\) at \(\color{black}{ x=a }\) is \(\color{black}{ f'(a) }\).
So, first you will need the derivative of the function \(\color{black}{ y=2x^2+2 }\)?
`Example:` Find the slope of the function \(\color{black}{ y=x^2+4 }\) at \(\color{black}{ x=3 }\). ----------------------------------------------------- `Solution:`\(\tiny\\[0.5em]\) \(\color{black}{ f(x)=x^2+4 }\) \(\color{black}{ f'(x)=2x+0 }\) \(\color{black}{ f'(x)=2x }\) Then, \(\color{black}{ f'(\color{red}{3})=2\color{red}{(3)}=6 }\).
So, for that example the answer is \(6\).
So, all you have to do is to find the derivative of the function (this will be the slope of when x=x), and then plug in x=3 into the derivative to find the slope at x=3.
so, finally, it would be "B". correct? @SolomonZelman
@3mar @DanJS ?^
Your function is y=2x^2 + 2 what is the derivative of that?
@DanJS not sute
I am sorry. I was not here! If you still need help, I am at your service!
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