Question

help please number 13

Answer 1

i dont understand whats going on with this concept

Answer 2

@zepdrix

Answer 3

@SolomonZelman

Answer 4

\(\color{black}{\displaystyle x=\sin t }\)
\(\color{black}{\displaystyle y=\csc t }\)

\(\color{black}{\displaystyle \csc x=\frac{1}{ \sin t} \quad \Longrightarrow \quad y=\frac{1}{x}}\)

Answer 5

how you get that ?

Answer 6

sin(t)*csc(t)=1 <---> csc(t)=1/sin(t)

Answer 7

(Just using a regular trig identity)

Answer 8

You have: \(\color{black}{ 0<t<\pi/2 }\):
So the domain is: \(\color{black}{ \sin(0)<\sin(t)<\sin(\pi/2) }\), and so, \(\color{black}{ 0<x<1 }\).

Answer 9

(Remark: What I did in line 2 is allowed because sin(t) is continuous, and always increases from t=0 to t=\(\pi\)/2.)