Algebra 2 Question A. The surface area S of the greenhouse is given by S = πr^2+πrl. Substitute 600 for S and then write an expression for l in terms of r. B. The volume V of the greenhouse is given by V = 1/2πr^2l. Write an equation that gives V as a polynomial function of r alone. ** l meaning length **
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Yes please
Of course. That is with my pleasure!
For A: The surface area S of the greenhouse is given by S = πr^2+πrl. Substitute 600 for S and then write an expression for l in terms of r. I think it is a simple substitution operation. Just replace S with 600 and solve for l, can you?
600 - πr^2 / πr = l
you mean this: \[\Large 600=πr^2+ πrl\] \[\Large 600-πr^2= πrl\] \[\Large\frac{ 600-πr^2 }{ πr }= l\] ??
Yes
For A\[\Huge\color{red}\checkmark\]
Ok good! Now for B, this is where I struggle
Now: B...easy In Sha' Allah B. The volume V of the greenhouse is given by V = 1/2πr^2l. Write an equation that gives V as a polynomial function of r alone. please type in the volume form in terms of r only. Can you?
\[V = (1/2πr^2) 600-πr^2/πr\]
Can you use the parentheses, please? It matters a lot!
\[V = (1/2πr^2) (600-πr^2/πr)\]
That makes sense! and it is away better!
Are there more steps/ can it be simplified anymore?
\[\Huge\color{DodgerBlue}{V=\frac{ 1 }{ 2 }\color{Brown }{\pi r}^2[\frac{ 600-\pi r^2}{ \color{Brown }{\pi r} }]}\] Can you cancel something?
the πr right? Then what happens with the exponent?
\[V=\frac{ 1 }{ 2 }^2\left( 600-πr^2 \right)\]
\[V=\frac{ 1 }{ 4}(600-πr^2)\]
"the πr right? " Yes, that is right!
\[\Huge\color{DodgerBlue}{V=\frac{ 1 }{ 2 }\color{Brown }{(\pi r)}*r[\frac{ 600-\pi r^2}{ \color{Brown }{\pi r} }]}\] Does it make sense now?
Yes
so it would be \[V = \frac{ 1 }{ 2 }r(600-πr^2)\]
\[\Huge\color{Chocolate }\checkmark\] Can you now "write an equation that gives V as a polynomial function of r alone"? that means: mutiply \(\frac{1}{2}\) by the parentheses!
\[V=300r-1.57r^3\]
\[V = -1.57r^3 +300r\]
\[V = -π(\frac{ 1 }{ 2 })r^3+300r\]
\[\Huge\color{Orchid }{V = -(\frac{ \pi }{ 2 })r^3+300r}\] \[\Huge\color{Orange }\checkmark\]
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