Will Medal: Find exact value of x: (Domain Inclusive)
ln(x)

Question

Will Medal: Find exact value of x: (Domain Inclusive)
ln(x) < 2

It's been a while since I've done logarithms :b
Am I supposed to multiply or do some weird exponent stuff [O:]

3mar · Answer

https://www.desmos.com/calculator/wocdgdnvfm Is that what you want?

mhchen · Answer

Getting x by itself is what I want

3mar · Answer

But you said "ln(x) < 2"?

mhchen · Answer

Yeah, there's a way to get x < something right?

3mar · Answer

ln(x) < 2: that means the "y" is less than 2, not x!

mhchen · Answer

$$\log_{e}{x} < 2$$$$x < something ~~~~or ~~~~x > something$$

I'm thinking x as more of a variable.

mhchen · Answer

Like, I've seen the answer, it's 
$$x < e^2$$ and there's like a sone weird step to it.

3mar · Answer

Oh yes,
I got you!

mhchen · Answer

Oh yeah and the domain is $$0 < x < e^2$$, we can get that part out of the way.
I'm wondering on how we simplified ln(x) < 2  to x < e^2

3mar · Answer

They are the same!

mhchen · Answer

Yeah, I know they're the same, but ln(x) < 2 gets simplified to x < e^2 somehow right?

Like I have to multiply ln(x) < 2 by <something> in order to get x by itself.

mhchen · Answer

I'll look up definition of a logarithm

3mar · Answer

I have to multiply ln(x) < 2 by <something>

No you have not

Do you know the idea of that?

3mar · Answer

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