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Just write out the equation and I will do the rest....... If correct will be rewarded with medal
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I will direct quote it. `Let P(t) denote the population at t years after 1993, then ` `P(0) = 94 million` `P(6) = 99 million ` `P(t) = P(0) e^(k t)` `Therefore ` `P(6) = P(0) e^(6 k) ` `99 = 94 e^(6 k) ` `e^(6 k) = 99/94 ` `6 k = ln (99/94) ` `k = ln (99/94) / 6 = 0.0086375 ` `Now that we have the value of k, we can estimate the population in 2005 ` `t = 2005 - 1993 = 12 ` `P(12) = P(0) e^( 12 k) = 94 e^( 12 (0.0086375) ) = 104.266 million`
Thx bro
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