Question

Please help will fan and medal!
what are the zeroes of y=x^2+14x+40?

Answer 1

I can solve this by factorization right?

Answer 2

standard form ax^2 +bx+c
when a=1 as you have, then you want to find two numbers that multiply to give c, but add up to give b
so list out the set of each 2 numbers that multiply to give 40
1 40
2 20
4 10
-1 -40
-2 -20
-4 -10

etc

now all of the signs are positive so our multipliers will be positive
so multiply to give 40, add to give 14
our set of multipliers will be 10 and 4
we know they are both positive hence

(x+10)(x+4)

so another example

x^2 + 4x+4

multipliers of 4
1 4
2 2
-1 -4
-2 -2

everything is positive so the multipliers are positive

multiply to give 4, but add to give 4
2 and 2

(x+2)(x+2)

Answer 3

try to use the same method for similar questions

Answer 4

Thank you so much!!!!! I will