Question

Do not know the process to solve this answer
2.05*10^-18= 2.18*10^-18 (1/Nf^2 - 1/Ni^2)

Answer 1

What are you solving for?

Answer 2

SO this is a question from Chemistry where we have a final reading and an initial reading. I am trying to find the final reading (Nf)

Answer 3

\[2.05*10^-18 = -2.18*10^-18 (\frac{ 1 }{ n _{f}^2 }-\frac{ 1 }{ n _{i}^2 })\]

Answer 4

You can find Nf in terms of Ni just by algebra.

Answer 5

\[-0.9404= (\frac{ 1 }{ n _{f}^2 }-\frac{ 1 }{ n _{i}^2 })\]

Answer 6

This is where i'm stuck. My teacher has -0.9404 = (1/nf^2 - 1/1^2)
then 0.0596 = 1/nf^2
But I dont know how she deducted the 1/1^2