Question

Is this correct?
http://prntscr.com/d7txx5

Answer 1

No.

Answer 2

\(\color{black}{2x+y=4 }\)
\(\color{black}{2x+y\color{red}{-2x}=4\color{red}{-2x} }\)
\(\color{black}{y=-2x+4 }\)

(What you wrote is a parallel line just 8 units below this one.)

Answer 3

Find the equation of a line perpendicular to \(\color{black}{y=mx+b }\), where \(\color{black}{m\ne0 }\).


The slope this line is \(\color{black}{m }\), therefore any perpendicular line will have a slope \(\color{black}{-1/m }\). Thus, \(\color{black}{y=\frac{-1}{m}x+n }\) will be perpendicular (for any n, because shifting it down or up doesn't have an impact on whether it's perpendicular or not).

Answer 4

So, basically, for all \(\color{black}{a,b\in\mathbb{R} }\) and \(\color{black}{m\ne 0 }\),
\(\color{black}{y=\frac{-1}{m}x+a }\) and \(\color{black}{y=mx+b }\) are perpendicular.

Answer 5

\[y=\frac{ 1 }{ 2 }x\]

Answer 6

Yes:)

Answer 7

Okay thanks!

Answer 8

yw