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Mathematics 8 Online
zarkam21 (zarkam21):

I know the answer is either A or B , just confused

zarkam21 (zarkam21):

OpenStudy (phi):

Let's try Choice A first, write down G(x) \[G(x) = x^2\] now replace all the x's with F(x) what do you get ?

zarkam21 (zarkam21):

G(F(x))=F(x)^2

OpenStudy (phi):

and we have to remember that F(x)^2 means (F(x) ) ^2 next we replace F(x) with 3x+1 we get \[ G(F(x)) = (3x+1)^2 \]

OpenStudy (phi):

I assume you know (3x+1)^2 is not the same as 3x^2+1

zarkam21 (zarkam21):

Yes so step one is to substitute all x's with f(x) Then you take out the f(x) and substitute the equation given

zarkam21 (zarkam21):

Yes I do know that

OpenStudy (phi):

ok, so choice A does not work.

zarkam21 (zarkam21):

Okay let me try choice b

zarkam21 (zarkam21):

G(F(x))=3x^2 right?

OpenStudy (phi):

The first step should be G(x) = 3x^2 becomes G(F(x) ) = 3(F(x))^2 now do the 2nd step

zarkam21 (zarkam21):

G(x)=x+1^2

zarkam21 (zarkam21):

G(F(x))=x+1^2

OpenStudy (phi):

ok, but you left out the 3 and you should have parens around x+1 (it's one thing) try again

zarkam21 (zarkam21):

G(F(x))=(3x+1)^2

zarkam21 (zarkam21):

Like that?

OpenStudy (phi):

almost. F(x) is (x+1) the 3 belongs "outside"

zarkam21 (zarkam21):

G(F(x))=3(x+1)^2

OpenStudy (phi):

yes. looks good, but it's not the answer we want.

zarkam21 (zarkam21):

Choice d then =)

zarkam21 (zarkam21):

I did it here on paper

OpenStudy (phi):

yes, choice D fyi, choice C gives G(F(x)) = 1 which is not what we want.

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