Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (alexis.madero):

help

OpenStudy (alexis.madero):

@Will.H @563blackghost

563blackghost (563blackghost):

O.o im seeing double

OpenStudy (will.h):

U can do it ghosty XD

563blackghost (563blackghost):

I know for the second part. Since it is an equilateral each angle can only be 60 degrees. So. \(\huge\bf{3a+4=60}\) Simplify for a. \(\huge\bf{6b=60}\) Simplify for b. \(\huge\bf{19c+3=60}\) Simplify for c.

OpenStudy (will.h):

The diagram ia confusing I'll have to make one of my own

OpenStudy (will.h):

Oh ghosty got it XD

563blackghost (563blackghost):

Well not the first part that one is confusing me a bit.

OpenStudy (will.h):

Well the whole question is confusing me XD

OpenStudy (will.h):

@Mathmale is the one

OpenStudy (alexis.madero):

lol i think im the one most confused of all

563blackghost (563blackghost):

Ooo ok. Due to the fact `PQ is congruent to QS` that would indicate isoceles triangle same applies to `QR is congruent to RS` so we gots to mark that one sec.

OpenStudy (will.h):

Is Qs a bisector?

OpenStudy (will.h):

If yes that would make it too easy

563blackghost (563blackghost):

563blackghost (563blackghost):

This would mean `RSQ` is congruent to `SQR` and `SRQ` is congruent to `QSP`.

563blackghost (563blackghost):

Does that make sense?

OpenStudy (alexis.madero):

kind of can you explain it in a simpler way if possible?

563blackghost (563blackghost):

Hmmmm.... Isosceles triangles have two congruent sides and angles. Since we are given that two sides in triangle RSQ are congruent that means it is an isosceles triangle. Since we are also given that two sides in triangle PQS are congruent that means that triangle is an isosceles triangle. This is how im proving it to be able to solve.

OpenStudy (alexis.madero):

ohhh okay makes much more sense

563blackghost (563blackghost):

We are given that `angle PRS` has an angle of `72`. Due to the fact we proved it is an isoceles triangle we would `subtract 180 from 72 and divide by 2` since two angles are congruent. This will find `angle RSQ and angle RQS`. \(\huge\bf{180-72=108}\) \(\huge\bf{108 \div 2 = 54}\) So `RSQ = 54` and `RQS = 54`.

563blackghost (563blackghost):

@princeevee I am explaining your question here

563blackghost (563blackghost):

Do you understand? @alexis.madero

OpenStudy (alexis.madero):

yes im getting it

563blackghost (563blackghost):

Ok good :) Its a bit complicated ^.^

OpenStudy (alexis.madero):

it is lol

563blackghost (563blackghost):

Now that we know that `RQS = 54` we can solve `SQP` since it lies on the same line which has a total degree of 180. So we subtract. \(\huge\bf{180-54 = 126}\) So `SQP = 126`. Now as said before this triangle has two congruent sides. So we would follow the same process as before. We would subtract this total `(126)` by 180 and then divide by 2 to find `PSQ` and `QPS`. \(\huge\bf{180-126=54}\) \(\huge\bf{54 \div 2 = 27}\) So `PSQ = 27` and `QPS = 27`.

OpenStudy (alexis.madero):

wow your just amazing at math ^.^ thannk you so much

563blackghost (563blackghost):

no problem :) Now comes the second part. We simplify to find a, b, and c. \(\huge\bf{3a+4=60}\) Subtract 4. \(\huge\bf{3a=56}\) Divide by 3/ \(\huge\bf{a=19}\)

563blackghost (563blackghost):

Simplify for b. \(\huge\bf{6b=60}\) Divide by 6. \(\huge\bf{b=10}\)

563blackghost (563blackghost):

Simplify c. \(\huge\bf{19c+3=60}\) Subtract 3 \(\huge\bf{19c=57}\) Divide by 19. \(\huge\bf{c=3}\)

563blackghost (563blackghost):

That should do it :)

OpenStudy (alexis.madero):

seriously your the best thanks for helping

563blackghost (563blackghost):

No problem :) Sorry couldnt answer on your thread @princeevee

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!