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Mathematics 14 Online
OpenStudy (poto):

Need help with dilation! http://prntscr.com/d88k8q

OpenStudy (poto):

@zepdrix

OpenStudy (poto):

@triciaal

OpenStudy (poto):

@sshayer

OpenStudy (triciaal):

one approach basically each length will change by the dilation factor. the center is (-8, 2) mark this spot. find the length of each point from the center multiply by the factor and that will be the new length

OpenStudy (poto):

Okay thanks Triciaal! :)

OpenStudy (poto):

I'll show you my result when I'm done, to make sure it's correct

OpenStudy (triciaal):

Disclaimer: I am not the best geometry person ---one approach

OpenStudy (tackopp):

Hey, how do you ask questions? Really need help with a question!

OpenStudy (poto):

So you said I have to multiply the length by the factor correct? And how would I find the points for the dilation?

OpenStudy (poto):

@triciaal

OpenStudy (mathmate):

@poto @triciaal gave you the geometric approach, i.e. working on the diagram. Please post what you get. If you wish, you could also calculate the results of the dilation (as a check) using the following procedure, which may seem complicated at the beginning, but very easy once you've seen the example. When dilation is about the origin O, with a scale factor k, then the dilation is, as you probably already know: \(D_k: (x,y)\rightarrow (kx,ky)\) If the dilation is about the centre of dilation located at C(a,b), then we need to do three steps: 1. translate the coordinate origin O to the centre of dilation C, call the new origin O'. 2. dilate, using the D operator as above 3. move the translated origin O' back to O. Recall that the translation operator, T, is given by: \(T_{a,b}: (x,y)\rightarrow (x+a,y+b)\) Then steps 1 to 3 above would read: \(D_{k,a,b}: (x,y)\rightarrow T_{a,b}\circ D_{k} \circ T_{-a,-b}\) where (a,b) is the centre of dilation, and k the scale factor and note that composite transformation occur from right to left. If we combine all the steps, we end up with a single transformation: \(D_{k,a,b}: (x,y)\rightarrow (k(x-a)+a,~k(x-b)+b) \) which is relatively simple. Example for the top vertex A(2,12)=A(x,y) and centre of dilation (a,b)=(-8,2), scale factor k=1/5 : Then \(A'(\frac{1}{5}(2-(-8))+(-8), \frac{1}{5}(12-2)+2)=(10/5-8,10/5+2)=(-6,4)\) I'll leave it to you to finish off the other three points, by the geometric method or the transformation method.

OpenStudy (poto):

Alright! Thanks Mathmate! :)

OpenStudy (mathmate):

You're welcome! :)

OpenStudy (triciaal):

Thank you @mathmate also another reminder how much I have forgotten @Poto there is the shorter approach

OpenStudy (mathmate):

@triciaal The geometric approach is much easier to work on, and much more visual and hence helps understanding of the concept. Please don't discount its value! The transformation approach was just another way to serve as a check.

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