Eliminate the parameter X=2cos t Y=1+sint
cos(t) = x/2 cos^2(t) = x^2/4 Now do something similar with y. Then add them up. The sum is 1 Would like medal and fan. -Credits to friend in skype!
Oops.. Suppose to be theta lol
An alternative approach: X=2cos t Y=1+sint Solve the first equation for cos t and the second for sin t. Now square both sides of both equations. Note that \[\sin ^{2}x+\cos ^{2}x=1\]
This fact will enable you to eliminate the trig functions and be left with a relationship in x and y only.
(x/2)^2+ (y-1)^2=1
This is where i get lost
@mathmale
@cazeh
it is hard i cant help sry dude :d
Lol okay
(x/2)^2 = x^2 / 4 \[(y-1)^2 = 1 - \frac{x^2}{4}\] convert to 1 fraction \[(y-1)^2 = \frac{4-x^2}{4}\] take sqrt \[y-1 = \frac{\pm \sqrt{4-x^2}}{2}\] \[y = 1 \pm \frac{\sqrt{4-x^2}}{2}\]
Oh could we actually do that to eliminate the parameter?
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